Answer:
a. NP
b. NP
c. Polar
d. Ionic
e. Polar
Explanation:
The way I did it was using the electronegativity of the elements mentioned and subtracted the pairs. For non polar the difference is 0-0.4, for polar it’s 0.4-2.0, for ionic it’s >2.0. I included the chart I used to find the electonegativity for the elements below.
B: 2.04, P: 2.19, difference is 0.15, so NP
Be: 1.57, Si: 1.9, difference is 0.33, so NP
C: 2.55, Na: 0.93, difference is 1.62, so Polar
Li: 0.98, O: 3.44, difference is 2.46, so Ionic
Mg: 1.31, N: 3.04, difference is 1.73, so Polar
If you really want I can explain why electronegativity affects the types of bonds, just comment below
