Answer :
The molarity of the diluted standard solution is obtained by calculation to be 0.015 M.
Recall the dilution formula;
C1V1 = C2V2
C1 = Initial concentration = 0.1140 M
V1 = initial volume = 6.50mL
C2 = Final concentration = ?
V2 = Final volume = 50.0mL
Making C2 the subject of the formula and substituting values;
C2 = C1V1/V2
C2 = 0.1140 M × 6.50mL/50.0mL
C2 = 0.015 M
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