The molarity of the NaOH solution required for the reaction is 0.186 M
We'll begin by writing the balanced equation for the reaction
H₂C₂O₄ +2NaOH —> Na₂C₂O₄ + 2H₂O
From the balanced equation above,
The mole ratio of the acid, H₂C₂O₄ (nA) = 1
The mole ratio of the base, NaOH (nB) = 2
From the question given above, the following data were obtained:
Volume of the acid, H₂C₂O₄ (Va) = 22.14 mL
Molarity of the acid, H₂C₂O₄ (Ma) = 0.105 M
Volume of the base, NaOH (Vb) = 25 mL
MaVa / MbVb = nA/nB
(0.105 × 22.14) / (Mb × 25) = 1/2
2.3247 / (Mb × 25) = 1/2
Cross multiply
Mb × 25 = 2.3247 × 2
Mb × 25 = 4.6494
Divide both side by 25
Mb = 4.6494 / 25
Therefore, the molarity of the base, NaOH solution is 0.186 M
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