Answer:
1 -9/7n
Step-by-step explanation:
[tex]\dfrac{1}{7}-3\left(\dfrac{3}{7}n-\dfrac{2}{7}\right)=\dfrac{1}{7}-\dfrac{3\cdot3}{7}n+\dfrac{3\cdot2}{7}=\dfrac{1}{7}+\dfrac{6}{7}-\dfrac{9}{7}n\\\\=\dfrac{1+6}{7}-\dfrac{9}{7}n=\boxed{1-\dfrac{9}{7}n}[/tex]
