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The damage done by a projectile on impact is correlated with
its kinetic energy. Calculate and compare the kinetic energies of
these three projectiles:
a) a 10.0-kg stone at 30.0 m/s
b) a 100.0-g baseball at 60.0 m/s
c) a 20.0-g bullet at 300. m/s

Answer :

Eduard22slygo

A. The kinetic energy of the stone is 4500 J

B. The kinetic energy of the baseball is 180 J

C. The kinetic energy of the bullet is 900 J

A. Determination of the kinetic energy of the stone

  • Mass (m) = 10 Kg
  • Velocity (v) = 30 m/s
  • Kinetic energy (KE) =?

KE = ½mv²

KE = ½ × 10 × 30²

KE = 5 × 900

KE = 4500 J

B. Determination of the kinetic energy of the baseball

  • Mass (m) = 100 g = 100 / 1000 = 0.1 Kg
  • Velocity (v) = 60 m/s
  • Kinetic energy (KE) =?

KE = ½mv²

KE = ½ × 0.1 × 60²

KE = 0.05 × 3600

KE = 180 J

C. Determination of the kinetic energy of the bullet

  • Mass (m) = 20 g = 20 / 1000 = 0.02 Kg
  • Velocity (v) = 300 m/s
  • Kinetic energy (KE) =?

KE = ½mv²

KE = ½ × 0.02 × 300²

KE = 0.01 × 90000

KE = 900 J

SUMMARY

  • Kinetic energy of stone = 4500 J
  • Kinetic energy of baseball = 180 J
  • Kinetic energy of bullet = 900 J

From the above, we see clearly that the stone has the highest kinetic energy followed by the bullet and then the baseball.

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