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need some help here

Answer:
69 and 30
Step-by-step explanation:
Using the formula with d = 96
[tex]T_{max}[/tex] = [tex]\frac{2(96)}{3}[/tex] + 5 = [tex]\frac{192}{3}[/tex] + 5 = 64 + 5 = 69 in
[tex]T_{min}[/tex] = [tex]\frac{96}{3}[/tex] - 2 = 32 - 2 = 30 in