Answer:
[tex]\huge\boxed{\sf 3x^2-4x+12}[/tex]
Step-by-step explanation:
[tex]=x(2x+3)+(x-3)(x-4)\\\\Using \ distributive \ property\\\\=(x)(2x)+(x)(3)+x(x-4)-3(x-4)\\\\=2x^2+3x+x^2-4x-3x+12\\\\Combining \ like \ terms\\\\= 2x^2+x^2+3x-3x-4x+12\\\\= 3x^2-4x+12\\\\\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807
