Answer:
D) 56π yd²
Step-by-step explanation:
The surface area of a cylinder is [tex]SA=2\pi rh+2\pi r^2[/tex]
Given a diameter of 4 yards, its radius must be 2 yards, which is half of it.
Now, we can determine the surface area of the cylinder:
[tex]SA=3\pi rh+2\pi r^2[/tex]
[tex]SA=2\pi(2)(12)+2\pi(2)^2[/tex]
[tex]SA=2\pi(24)+2\pi(4)[/tex]
[tex]SA=48\pi+8\pi[/tex]
[tex]SA=56\pi[/tex]
Therefore, the surface area of the cylinder is 56π yd².
