What is the value of y?

Answer:
[tex] \sf {\underline{2 \sqrt{5} }}[/tex]
Explaination :
[tex] \sf \: \angle FDE \: = 90 \degree \\ \sf \: by \: pythagoras \: theoram \\ \sf {6}^{2} = {y}^{2} + {4}^{2} \\ \sf{y}^{2} = {6}^{2} - {4}^{2} \\ \sf {y}^{2} = 36 - 16 \\ \sf{y}^{2} = 20 \\ \sf \: y = \sqrt{20} = \sqrt{4 \times 5} = 2 \sqrt{5} [/tex]
The value of y in the triangle is 2√5
The triangle above is a right angle triangle.
Characteristics of a right angle triangle:
Using Pythagoras theorem
where
c = hypotenuse(longest side)
a and b are the 2 other legs.
Therefore,
6² = 4² + y²
36 = 16 + y²
y² = 36 - 16
y² = 20
y = √20
y = 2√5
learn more on right angle triangle here:https://brainly.com/question/3770177?referrer=searchResults