2NH3 + MgSO4 + 2H20-→ Mg(OH)2 + (NH4)2SO4
Using the chemical equation above answer the following questions.
If I have 4.6 moles of MgSO, and 5.4 moles of NH3 which one is the limiting
reactant? You must show your work for credit.

The limiting reagent is the reactant that is completely used up in a reaction and thus determines when the reaction stops. From the reaction stoichiometry, the exact amount of reactant needed to react with another element can be calculated.

2NH3 + MgSO4 + 2H20-→ Mg(OH)2 + (NH4)2SO4

For limiting reagent:-

MgSO4= moles / stoichiometry coefficient

⇒ 4.6/1

NH3 = moles / stoichiometry coefficient

⇒ 5.4/2

⇒ 2.7

HENCE, the limiting reagent is - NH3.

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2NH3 + MgSO4 + 2H20-→ Mg(OH)2 + (NH4)2SO4 Using the chemical equation above answer the following questions. If I have 4.6 moles of MgSO, and 5.4 moles of NH3 which one is the limiting reactant? You must show your work for credit.

Answer :

What is a limiting reagent?

Go Teaching: Other Questions

2NH3 + MgSO4 + 2H20-→ Mg(OH)2 + (NH4)2SO4
Using the chemical equation above answer the following questions.
If I have 4.6 moles of MgSO, and 5.4 moles of NH3 which one is the limiting
reactant? You must show your work for credit.