Can someone please help me with questions 13 and 14?

Answer: #13 is 26, #14 is 18
Step-by-step explanation:
13.
The whole line has length [tex]8x - 20[/tex], and [tex]AB = BC = 3x - 1[/tex]. Thus
[tex](3x -1) + (3x-1)=8x-20\\6x - 2 = 8x - 20\\18 = 2x\\x = 9[/tex]
Now we plug this into [tex]3x - 1[/tex] (since this is the length of BC) to get
[tex]3(9) - 1 = \boxed{26}[/tex].
14.
We can use the fact that CG = GD, so [tex]5x - 1 = 7x - 13[/tex] and thus [tex]x = 6[/tex].
We know [tex]EG = EF - GF[/tex], so
[tex]EG = (6x - 4) - 13 = (6 \cdot 6 - 4) - 14 = \boxed{18}.[/tex]