how to solve x in this equation!

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Fieryanswererftgo Fieryanswererftgo · Answer 1

Answer:

x = 1/10

Step-by-step explanation:

[tex]2^{x} = 2^{\frac{8}{5} } / 2^{\frac{6}{4} }[/tex]

[tex]2^{x} =[/tex] [tex]2^{\frac{8}{5}-\frac{6}{4} }[/tex]

[tex]2^{x} =[/tex] [tex]2^{\frac{1}{10} }[/tex]

[tex]x = \frac{1}{10}[/tex]

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DᴀʀᴋPᴀʀᴀᴅᴏxgo DᴀʀᴋPᴀʀᴀᴅᴏxgo · Answer 2

[tex]\huge \bf༆ Answer ༄[/tex]

Let's solve ~

[tex]{ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf4 {}^{ \frac{ 3 }{4} } \times 2 {}^{ {x}^{} } = 16 {}^{ \frac{2}{5} } [/tex]

[tex]{ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf(2 {}^{2} ) {}^{ \frac{ 3 }{4} } \times 2 {}^{ {x}^{} } =( 2 {}^{4}) {}^{ \frac{2}{5} } [/tex]

[tex]{ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf2 {}^{} {}^{ \frac{ 3 }{2} } \times 2 {}^{ {x}^{} } =2 {}^{} {}^{ \frac{8}{5} } [/tex]

[tex]{ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf2 {}^{} {}^{( \frac{ 3 }{2} + } {}^{ {x)}^{} } =2 {}^{} {}^{ \frac{8}{5} } [/tex]

[tex]{ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \frac{3}{2} + x = \frac{8}{5} [/tex]

[tex]{ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf x = \frac{8}{5} - \frac{3}{2} [/tex]

[tex]{ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf x = \frac{16 - 15}{10} [/tex]

[tex]{ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf x = \frac{1}{10} \: \: or \: \: \: 0.1[/tex]