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Show all calculations. 1. 2 C 4 H 10 + 13 O 2 -> 8 CO 2 + 10 H 2 O a) what mass of O 2 will react with 400 g C 4 H 10? b) how many moles of water are formed in a)?

Answer :

[tex]\\ \tt\hookrightarrow 2C_4H_10+13O_2\longrightarrow 8CO_2+10H_2O[/tex]

  • 13mol of O_2 reacts with 2mols of C_4H_10.
  • 7.5mol of O_2 reacts with 1mol of C_4H_10

No of moles:-

[tex]\\ \tt\hookrightarrow \dfrac{Given\:mass}{Molar\:mass}[/tex]

[tex]\\ \tt\hookrightarrow \dfrac{400}{58}[/tex]

[tex]\\ \tt\hookrightarrow 6.89mol[/tex]

Now

Moles of O_2

[tex]\\ \tt\hookrightarrow 7.5(6.89)=51.6mol[/tex]

Mass of O_2

[tex]\\ \tt\hookrightarrow 51.6(32)=1651.2g[/tex]

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