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Which is the equation of a hyperbola with directrices at y = Β±2 and foci at (0, 4) and (0, βˆ’4)?

a.) x squared over 8 minus y squared over 16 equals 1
b.) y squared over 16 minus x squared over 8 equals 1
c.) x squared over 8 minus y squared over 8 equals 1
d.) y squared over 8 minus x squared over 8 equals 1

HELP I WILL GIVE BRAINLIEST Which Is The Equation Of A Hyperbola With Directrices At Y 2 And Foci At 0 4 And 0 4 A X Squared Over 8 Minus Y Squared Over 16 Equa class=

Answer :

Answer:

I think it's A

Step-by-step explanation:

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Answer:

The answer is D the last optiony^2/8 -x^2/8=1

Step-by-step explanation:

Center:

(0,0)

Vertices:

(0,2√2),(0,βˆ’2√2)

Foci:

(0,4),(0,βˆ’4)

Eccentricity:

√2

Focal Parameter:

1

Asymptotes:

y=x, y=βˆ’x

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