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032. A 25.0 kg bicycle is traveling at a speed of 10.0 m/s.
a. If the bike comes to rest in 2.0 s, what is the magnitude
of its acceleration?
b. What net force is needed to provide this acceleration?
c. How far will the bike travel in the 2.0 s?

Answer :

Answer:

See below

Explanation:

acceleration = change in velocity / change in time

                     =   - 10 m/ s  /  2 sec =  -  5 m /s^2    = 5 m/s^2 (magnitude)

F = ma    =   25 kg * 5 m/s^2 = 125 N

x = vo t + 1/2 at ^2

  = 10 (2)  + 1/2 ( -5)(2^2 ) = 10 meters

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