[tex]\qquad \qquad\huge \underline{\boxed{\sf Answer}}[/tex]
Let's use Trigonometric relations to find the value of hypotenuse (x), in the given right angled Triangle.
[tex] \qquad \sf \dashrightarrow \: \cos(45) = \dfrac{11}{{x}^{} } [/tex]
[tex] \qquad \sf \dashrightarrow \: \dfrac{1}{ \sqrt{2} } = \dfrac{11}{x} [/tex]
[tex] \qquad \sf \dashrightarrow \: x = 11 \times \sqrt{2} [/tex]
[tex] \qquad \sf \dashrightarrow \:x = 11 \sqrt{2 \:} \: units[/tex]
