[tex]\bold{\huge{\pink{\underline{Solution}}}}[/tex]
[tex]\bold{\underline{Given :-}}[/tex]
- We have given two sides of the triangle that is 10cm height and 22cm base
[tex]\bold{\underline{To\: Find :-}}[/tex]
- We have to find the value of x°
[tex]\bold{\underline{Let's\: Begin :-:-}}[/tex]
Here, we will use the concept of trigonometric ratios that is tan Φ , sinΦ , cos Φ etc.
[tex]\bold{ We\: know \: that, }[/tex]
[tex]\bold { Sin Φ = }{\bold{\frac{Perpendicular}{Hypotenuse}}}[/tex]
[tex]\bold{ Cos Φ = }{\bold {\frac{Base}{Hypotenuse}}}[/tex]
[tex]\bold{ tan Φ = }{\bold{\frac{Perpendicular}{Base}}}[/tex]
Here, we have Perndicular height and base of the given triangle, so we will use tan Φ as a reference for finding the value of x°
[tex]\sf{ tan Φ = }{\sf{\frac{10}{22}}}[/tex]
[tex]\sf{ tan Φ = }{\sf{\frac{5}{11}}}[/tex]
[tex]\sf{ tan Φ = 0.45}[/tex]
[tex]\sf{ tan x° = 27° }[/tex]
[tex]\sf{ Hence, \: The\: value \:of\: x°\: is\: 27°}[/tex]
