0.25 mL of the stock solution would be taken using a serological pipet and mixed with 49.75 mL of water in the measuring cylinder.
In order to prepare 50 mL, 0.05 M HCl from 10M stock, the volume of the stock that would be needed first needs to be calculated using the dilution equation:
M1V1 = M2V2
In this case, V1 is what we are looking for:
10V1 = 0.05 x 50
v1 = 0.25 mL
Thus, 0.25 mL of the stock is needed.
Hence, the solution can be prepared by measuring 49.75 mL of distilled water into the 100 mL cylinder and then using the 10 mL serological pipet to take 0.25 mL from the stock solution into the measured distilled water in the cylinder to make the 50 mL mark.
More on solution preparation can be found here: https://brainly.com/question/20910830
