A quadratic equation has an exponent of 2, and it has the form [tex]y = ax^2 + bx + c[/tex]
How to determine the axis of symmetry
Assume the quadratic equation is:
[tex]y\ =\ 2x^{2\ }-\ 4x\ \ -\ 6[/tex]
See attachment for the graph of the quadratic function
The axis of symmetry is the line that divides the quadratic function into equal segments
Hence, the axis of symmetry of [tex]y\ =\ 2x^{2\ }-\ 4x\ \ -\ 6[/tex] is x = 1
How to determine the vertex
This is the minimum or the maximum point on the graph
Hence, the vertex is (1,-8)
How to determine the y-intercept
This is the point where the graph crosses the y-axis
Hence, the y-intercept is y = -6
How to determine the x-intercept
This is the point where the graph crosses the x-axis
Hence, the x-intercepts are x = -1 and x = 3
Read more about quadratic functions at:
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