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Answer :

Answer:

[tex](foh)(x)=-x^2 +6x+31[/tex]

Step-by-step explanation:

[tex]\huge f(x)=13-x\ \ \ \ \ \ h(x)=x^2-6x-18 \\ \\(foh)(x)=f[h(x)]=13-(x^2-6x-18)=-x^2 +6x+31[/tex]