Answer:
Part A: 12 < 4[tex]x[/tex] < 24 (OR 3 < [tex]x[/tex] < 6)
Part B: the length [tex]x[/tex] needs to be bigger than 3 ft but smaller than 6 ft
Part C: Because the area must be more than 12 square feet and the width is 4 feet, the length must be greater than 3 feet.
Step-by-step explanation:
Part A
- Area of rectangle = width x length
We are told that the width = 4 ft
Let [tex]x[/tex] = length
Therefore, area = 4[tex]x[/tex]
The area needs to be more than 12 ft² but less than 24 ft²
Therefore, 12 < 4[tex]x[/tex] < 24
Part B
12 < 4[tex]x[/tex] < 24
Divide everything by 4: 3 < [tex]x[/tex] < 6
So the length [tex]x[/tex] needs to be bigger than 3 ft but smaller than 6 ft
Part C
Because the area must be more than 12 square feet and the width is 4 feet, the length must be greater than 3 feet.
