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At the end of an amusement park ride, it is desirable to bring a gondola to a stop without having the acceleration exceed 3 g. If the total mass of the gondola and its occupants is 1,727 kg, what is the maximum allowed braking force

Answer :

Onyebuchinnajigo

The break force of the gondola in the amusement park ride is 50,773.8 N.

Break force of the gondola

The break force of the gondola in the amusement park ride, is calculated by applying Newton's second law of motion as shown below;

F = ma

where;

  • m is the total mass = 1,727 kg
  • a is acceleration = 3g = 3 x 9.8 m/s² = 29.4 m/s²

F = 1,727 x 29.4

F = 50,773.8 N

Thus, the break force of the gondola in the amusement park ride is 50,773.8 N.

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