Answer :
3 m/s² is the answer.
Explanation:
Given:-
Speed = 6.0 m/s
Time = 2.0 s
Average acceleration = ?
Assume initial speed S(initial) as 0 as it started from rest position to movement.
Final speed of S(final) is 6
Now, we can find it,
[tex]Average \: acceleration = \frac{speed \: change}{time}[/tex]
[tex] = > Av.\: accel. = \frac{S^{final} -S^{initial} }{T}[/tex]
[tex] \: \: \: \: = > \frac{(6 - 0)}{2}[/tex]
[tex] = > \frac{6}{2} [/tex]
Reducing to lowest terms,
[tex] = > 3 \: m/ {s}^{2} [/tex]
Hence, the average acceleration of the bus is 3 m/s²