Answer :
Answer:
first term :9=a
common difference: 2 =d
A6=a+5d
=9+5(2)
=19
no of terms =9
[tex]s{n} = \frac{n}{2} (a + an) \\ = \frac{6}{2} (9 + 19) \\ = 3(28) \\ = 84[/tex]
Answer:
first term :9=a
common difference: 2 =d
A6=a+5d
=9+5(2)
=19
no of terms =9
[tex]s{n} = \frac{n}{2} (a + an) \\ = \frac{6}{2} (9 + 19) \\ = 3(28) \\ = 84[/tex]