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Answer :

Indrawboygo

pH = - log [H⁺]

pH = 7.5

[tex]\tt [H^+]=10^{-7.5}=3.16\times 10^{-8}[/tex]

pH + pOH = 14

7.5 + pOH = 14

pOH = 6.5

[tex]\tt [OH^-]=10^{-6.5}=3.16\times 10^{-7}[/tex]

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