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Mathematics

Answered

The length of a rectangle is 16 cm less than quadruple the width. If the perimeter is 28 cm,
what is the length and the width?

Answer :

Subbhygo Subbhygo

Width = x cm
Length = 4x - 16

Perimeter = x + x + 4x -16 + 4x - 16
28 = 10x -32

(+ 32 to both sides)

60 = 10x

6 = x

Width = 6cm

Length = (6x4) - 16
= 8cm

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