A. The balanced equation for the reaction is
2C₂H₂ + 5O₂ —> 4CO₂ + 2H₂O
B. The volume of the oxygen gas required to burn 0.700 L of acetylene gas is 1.75 L
C. The volume of carbon dioxide gas produced is 1.4 L
D. The volume of water vapor produced is 0.7 L
The balanced equation for the reaction between acetylene gas (Câ‚‚Hâ‚‚) and oxygen gas (Oâ‚‚) is given below
2C₂H₂ + 5O₂ —> 4CO₂ + 2H₂O
2C₂H₂ + 5O₂ —> 4CO₂ + 2H₂O
Since the reaction occurred at standard temperature and pressure, we can thus say that:
From the balanced equation above,
2 L of Câ‚‚Hâ‚‚ reacted with 5 L Oâ‚‚.
Therefore,
0.7 L of C₂H₂ will react with = (0.7 × 5) / 2 = 1.75 L of O₂
Thus, 1.75 L of Oâ‚‚ is needed for the reaction
2C₂H₂ + 5O₂ —> 4CO₂ + 2H₂O
From the balanced equation above,
2 L of Câ‚‚Hâ‚‚ reacted to produce 4 L of COâ‚‚
Therefore,
0.7 L of C₂H₂ will react to produce = (0.7 × 4) / 2 = 1.4 L of CO₂
Thus, 1.4 L of COâ‚‚ were produced
2C₂H₂ + 5O₂ —> 4CO₂ + 2H₂O
From the balanced equation above,
2 L of Câ‚‚Hâ‚‚ reacted to produce 2 L of Hâ‚‚O
Therefore,
0.7 L of Câ‚‚Hâ‚‚ will also react to produce 0.7 L of Hâ‚‚O
Thus, 0.7 L of Hâ‚‚O was produced
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