In the questions and with the answers it can be deduced that CD is half the sum of the other two lines given
Q.6
(AB + FG)/2 = CD
(7 + 11)/2 =18/2= 9= CD
Q7
(FG + AB)/2 = CD
FG + AB = 2CD
AB = 2CD - FG
AB = 2(13) - 22
AB = 26 - 22
AB = 4
Q8
(BA + GF)/2 = DC
BA + GF = 2DC
GF = 2DC - BA
GF = 2(32) - 17= 64 - 17 = 47
I think with this explanation u can do the rest urself
Hope it’s helpful