Answer :
The cost of 800 bricks having dimensions of [tex]7\frac{3}{4} \ by\ 3\frac{1}{2} \ by \ 2\frac{1}{2}[/tex] at a cost of $0.07 per in.³ is $3,797.5
How can the cost of 800 bricks to be used for the building be found?
The dimensions of the brick are;
[tex]\mathbf{7\frac{3}{4} \ by\ 3\frac{1}{2} \ by \ 2\frac{1}{2}}[/tex]
Cost of a cubic inch of brick = $0.07
The volume of 1 brick is therefore;
[tex]Volume \ of \ 1 \ brick \ V_1= 7\frac{3}{4} \ \times \ 3\frac{1}{2} \ \times \ 2\frac{1}{2} = \mathbf{67\frac{13}{16}}[/tex]
The volume occupied by 800 bricks is therefore;
[tex]Volume \ of \ 800 \ bricks \ V_{800} = 67\frac{13}{16} \times 800 =\mathbf{ 54250}[/tex]
Given that the dimensions of the bricks are in inches, the volume of 800 bricks is therefore;
V₈₀₀ = 54,250 in.³
The cost of 800 bricks is therefore;
Total cost = 54,250 in.³ × $0.07 = $3,797.5
The cost of 800 bricks is $3,797.5
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