Answer:
[tex]\frac{-23}{120}[/tex]
Step-by-step explanation:
[tex](\frac{3}{5}*\frac{-10}{9})+(\frac{-4}{5}*\frac{1}{-8})-(\frac{2}{5}*\frac{-15}{16})\\\\(\frac{1}{1}*\frac{-2}{3})+(\frac{-1}{5}*\frac{1}{-2})-(\frac{1}{1}*\frac{-3}{8})\\\\\frac{-2}{3} +\frac{1}{10} -\frac{-3}{8}\\\\\frac{-2}{3} +\frac{1}{10} +\frac{3}{8}\\\\\frac{-80}{120} +\frac{12}{120} +\frac{45}{120}\\\\\frac{-68}{120} +\frac{45}{120}\\\\\frac{-23}{120}[/tex]
Hope this helps!
