Assuming all these triangles are similar:
5. [tex]\frac{5x}{45}= \frac{20}{36} \\\frac{x}{9} =\frac{5}{9} \\9x = 45\\x =5[/tex]
6.[tex]\frac{3x -5}{(3x-5) + 10} =\frac{28-8}{28} \\\frac{3x-5}{3x+5} =\frac{20}{28} \\20(3x+5) = 28(3x-5)\\60x + 100 = 84x-140\\24x=240\\x =10[/tex]
Sorry for the weird formatting, hope it helped!
