Answer:
[tex]\angle RSC[/tex]
Step-by-step explanation:
Since the sum of all angles in a triangle is [tex]180^\circ[/tex], we can write [tex]\angle QSR[/tex] as [tex]180^\circ-(\angle SQR+\angle QRS)[/tex]. By the linear pair postulate, [tex]\angle RSC=180^\circ-\angle QSR[/tex].
Substituting, we have
[tex]\angle RSC=180^\circ-\angle QSR[/tex]
[tex]=180^\circ-(180^\circ-(\angle SQR+\angle QRS))[/tex]
[tex]=\angle SQR + \angle QRS[/tex],
as desired.