Answer:
45000Kgms is the required change in momentum .
Explanation:
As Per given Question
Mass of truck m = 3000Kg
Initial velocity u = 10m/s
Final velocity v = 25m/s
Calculating the change in velocity
→∆v = 25 - 10
→ ∆v = 15m/s
[tex] \bf \Delta \: p = m (\Delta\:v)[/tex]
On substituting the value we get
[tex] \implies\bf \Delta \: p = 3000 \times (15) \\ \\ \implies\bf \Delta \: p = 45000kgm {s}^{} [/tex]
So, the change in momentum is 45000Kgms
