itβs number 11. find the value of x to the nearest tenth. please help thank you!

Answer:
d
Step-by-step explanation:
using the tangent ration in the left- side right triangle
tan56 = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{115}{y}[/tex] ( y represents the adjacent side )
multiply both sides by y
y Γ tan56Β° = 115 ( divide both sides by tan56Β° )
y = [tex]\frac{115}{tan56}[/tex] β 77.6
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using the tangent ratio in the large outer right triangle
tan35Β° = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{115}{x+y}[/tex] ( multiply both sides by x + y )
(x + y) Γ tan35Β° = 115 ( divide both sides by tan35Β° )
x + y = [tex]\frac{115}{tan35}[/tex] β 164.2
then
x + 77.6 = 164.2 ( subtract 77.6 from both sides )
x = 86.6
Answer:
Step-by-step explanation:
[tex]tan \ 56 =\dfrac{opposite \ side }{adjacent \ side}\\\\\\1.4825=\dfrac{115}{y}\\\\y=\dfrac{115}{1.4825}\\\\\\[/tex]
y = 77.6
[tex]tan \ 35 =\dfrac{115}{x+77.6}\\\\0.7*(x +77.6) =115\\\\x + 77.6 =\dfrac{115}{0.7}\\\\[/tex]
x + 77 .57 = 164.2
x = 164.2 - 77.6
x = 86.6