Answer :
Step-by-step explanation:
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Answer:
[tex]x=1,\: x=2[/tex]
Step-by-step explanation:
To be honest, you don't need the quadratic formula as you can just factor the polynomial after setting it equal to 0:
[tex]x^2-3x=-2\\\\x^2-3x+2=0\\\\(x-1)(x-2)=0\\\\x=1,\: x=2[/tex]
If you really need to use the quadratic formula, here's the process:
[tex]ax^2+bx+c=0\\\\x^2-3x+2=0\\\\x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x=\frac{-(-3)\pm\sqrt{(-3)^2-4(1)(2)}}{2(1)}\\\\x=\frac{3\pm\sqrt{9-8}}{2}\\\\x=\frac{3\pm\sqrt{1}}{2}\\\\x=\frac{3\pm1}{2}\\x_1=\frac{3-1}{2}\\ \\x_1=\frac{2}{2}\\\\x_1=1\\\\x_2=\frac{3+1}{2}\\\\x_2=\frac{4}{2}\\ \\x_2=2[/tex]