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The plates of a parallel-plate capacitor are oppositely charged and attract each other. Find the expression for the force one plate exerts on the other.

Answer :

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The force exerted by one plate for two parallel plates arrangement is F = QE/2.

Force one plate exerts on the other

The force exerted by one plate for two parallel plates arrangement is given as follows;

F = QE/2

where;

Q is the charge on one plates
E is the electric field due to the charge
F is force exerted by one plate

Thus, the force exerted by one plate for two parallel plates arrangement is F = QE/2.

Learn more about force between parallel plates here: https://brainly.com/question/13590045

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