For triangle ABC, which one is equal to sine A? Group of answer choices sine B tangent C cosine C cosine B

Answer:
sin(A) = cos(C)
Step-by-step explanation:
Trig ratios:
[tex]\mathsf{\sin(\theta)=\dfrac{O}{H} \ \ \ \cos(\theta)=\dfrac{A}{H} \ \ \ \tan(\theta)=\dfrac{O}{A}}[/tex]
(where [tex]\theta[/tex] is the angle, O is the side opposite the angle, A is the side adjacent to the angle, H is the hypotenuse, of a right triangle)
[tex]\mathsf{\sin(A)=\dfrac{BC}{AC}}[/tex]
[tex]\mathsf{\cos(C)=\dfrac{BC}{AC}}[/tex]
Therefore, sin(A) = cos(C)