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Answered

(02.05 MC)
Using the completing-the-square method, rewrite f(x) = x2 - 6x + 2 in vertex form.
Of(x) = (x - 3)2
Of(x) = (x - 3)2 + 2
Of(x) = (x - 3)2 - 7
Of(x) = (x - 3)2 + 9

Answer :

Semsee45go

Answer:

[tex]f(x)=(x-3)^2-7[/tex]

Step-by-step explanation:

Use the formula:

[tex]x^2+bx+c \implies (x+\frac{b}{2})^2-(\frac{b}{2}{)^2+c[/tex]

[tex]f(x) = x^2 - 6x + 2[/tex]

[tex]\implies f(x)=(x-\frac62)^2-(\frac62)^2+2[/tex]

[tex]\implies f(x)=(x-3)^2-3^2+2[/tex]

[tex]\implies f(x)=(x-3)^2-9+2[/tex]

[tex]\implies f(x)=(x-3)^2-7[/tex]

[tex]\\ \rm\hookrightarrow x^2-6x+2[/tex]

[tex]\\ \rm\hookrightarrow x^2-2(3)(x)+2[/tex]

[tex]\\ \rm\hookrightarrow x^2-2(3x)+3^2-3^2+2[/tex]

  • 3^2-3^2=0

[tex]\\ \rm\hookrightarrow (x-3)^2-9+2[/tex]

[tex]\\ \rm\hookrightarrow (x-3)^2-7[/tex]

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