find an equation for the line below

Answer:
[tex]y=\frac{1}{4}x+\frac{11}{4}[/tex]
Step-by-step explanation:
Slope (m) formula: [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
(-3, 2) and (5, 4):
[tex]m=\frac{y_2-y_1}{x_2-x_1} \\\\m=\frac{4-2}{5-(-1)} \\\\m=\frac{4-2}{5+3} \\\\m=\frac{2}{8} \\\\m=\frac{1}{4}[/tex]
[tex]y=mx+b[/tex]
[tex]y=\frac{1}{4} x+b[/tex]
(-3, 2)
[tex]y=\frac{1}{4} x+b\\\\2=\frac{1}{4}(-3)+b\\\\2=-\frac{3}{4}+b\\\\4(2=-\frac{3}{4}+b)\\\\8=-3+4b\\\\+3 +3\\\\11=4b\\\\/4 /4\\\\11/4=b[/tex]
[tex]y=\frac{1}{4}x+\frac{11}{4}[/tex]
Hope this helps!