Answer :
C2H6(g)⟶2C(s)+3H2(g)ΔH=31kJ/mol
Therefore,
2C(s)+3H2(g)⟶C2H6(g)ΔH=−31kJ/mol
As we know that the heat of formation is same as the heat of reaction when one mole of the product is formed.
Hence the heat of formation of ethane is −31kJ/mol.
C2H6(g)⟶2C(s)+3H2(g)ΔH=31kJ/mol
Therefore,
2C(s)+3H2(g)⟶C2H6(g)ΔH=−31kJ/mol
As we know that the heat of formation is same as the heat of reaction when one mole of the product is formed.
Hence the heat of formation of ethane is −31kJ/mol.