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Chemistry

Answered

What volume of a 0. 120 m cai2 solution would contain 0. 078 mol of the solute?.

Answer :

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Answer:650 mL

Explanation:

Remember that Molarity = mol/L. Rearranging the equation to solve for liters you get L = mol/Molarity.

80x10-3 mol / 12x10-2 M = 6.5x10-1 L

6.5x10-1 L (1x103) = 6.5x10 2 mL = 650mL

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