Answer:
0.02 seconds
Step-by-step explanation: A 70kg man jumps 1.00 meters down onto a concrete walkway. His downward motion stops in 0.02 seconds.
Answer:
1.25m
Step-by-step explanation:
v=u+gt
5=0+10t
5=10t
t=0.5s
s=ut+1/2gt^2
=0+(0.5×10×(0.5)^2)
=1.25m
