Answer :
Answer:
40 kcal
Explanation:
Heat required to melt
1 g
of ice at
0°C
is approximately
80 cal
. This is also called latent heat of fusion of ice.
For
500 g
of ice
Q
=
500
g
×
80
cal
g
=
40000 cal = 40 kcal
Answer:
40 kcal
Explanation:
Heat required to melt
1 g
of ice at
0°C
is approximately
80 cal
. This is also called latent heat of fusion of ice.
For
500 g
of ice
Q
=
500
g
×
80
cal
g
=
40000 cal = 40 kcal