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A professional golfer swings a golf club, striking a golf ball that has a mass of 55.0 g. The club is in contact with the ball for only 0.00410 s. After the collision, the ball leaves the club at a speed of 32.0 m/s. What is the magnitude of the average force (in N) exerted on the ball by the club?

Answer :

Asuwafohjamesgo

The magnitude of the average force exerted on the ball by the club is 429.27 N.

What is force?

Force can be defined as the product of mass and acceleration

To calculate the force exerted on the ball by the club, we use the formula below.

Formula:

  • F = m(v-u)/t............ Equation 1

Where:

  • F = Force exerted on the ball
  • m = mass of the ball
  • v = Final velocity
  • u = initial velocity
  • t = time

From the question,

Given:

  • m = 55 g = 0.055 kg
  • u = 0 m/s
  • v = 32 m/s
  • t = 0.0041 s

Substitute these values into equation 1

  • F = 0.055(32-0)/0.0041
  • F = 429.27 N

Hence, The magnitude of the average force exerted on the ball by the club is 429.27 N.

Learn more about force here: https://brainly.com/question/18762601

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