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Mathematics

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What are the solution(s) for the following quadratic equation?
f(x)=5x^2+2x-7

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Answer :

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[tex]\\ \rm\rightarrowtail 5x^2-2x-7=0[/tex]

[tex]\\ \rm\rightarrowtail 5x^2-7x+5x-7=0[/tex]

[tex]\\ \rm\rightarrowtail x(5x-7)+1(5x-7)=0[/tex]

[tex]\\ \rm\rightarrowtail (x-1)(5x-7)=0[/tex]

[tex]\\ \rm\rightarrowtail x=1,7/5[/tex]

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