[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]
Let's solve for x ~
[tex]\qquad \sf \dashrightarrow \:12 {x}^{2} - 36x = 0[/tex]
[tex]\qquad \sf \dashrightarrow \:12 x({x}^{} - 3) = 0[/tex]
[tex]\qquad \sf \dashrightarrow \:12x = 0 \: \: or \: \: x - 3 = 0[/tex]
[tex]\qquad \sf \dashrightarrow \:x = 0 \: \: or \: \: x = 3[/tex]
Therefore, the possible values of x are 0 and 3
