Answer:
X ~ B(n, p)
Given: X ~ B(2, 5/17)
⇒ n = 2
⇒ p = 5/17
Binomial distribution formula:
[tex]\sf P(X = x) = nC_x (1-p)^{(n-x)}p^x[/tex]
As n = 2, calculate P(X = 0), P(X = 1) and P(X = 2):
[tex]\sf P(X = 0) = 2C0 (\frac{12}{17})^{(2-0)}(\frac{5}{17})^0=\dfrac{144}{289}}[/tex]
[tex]\sf P(X = 1) = 2C1 (\frac{12}{17})^{(2-1)}(\frac{5}{17})^1=\dfrac{120}{289}}[/tex]
[tex]\sf P(X = 2) = 2C2 (\frac{12}{17})^{(2-2)}(\frac{5}{17})^2=\dfrac{25}{289}}[/tex]
**Probability Distribution Table attached**
