[tex]x+y = 5~~...(i)\\\\2x-y = 1~~...(ii)\\\\\text{From (i):}\\\\x+y = 5\\\\\implies x = 5-y~~~.....(iii)\\\\\text{Substitute equation (iii) in equation (ii):}\\ \\2(5-y)-y = 1\\\\\implies 10 - 2y -y = 1\\\\\implies 3y = 9\\\\\implies y = \dfrac 93 = 3\\\\\text{Substitute y= 3 in equation (iii):}\\\\x= 5-3 = 2\\\\\text{Hence,}~ (x,y) = (2,3)[/tex]
