Answer:
center = (3, 0)
radius = 2
Step-by-step explanation:
Standard equation of a circle: [tex]\sf (x-h)^2+(y-k)^2=r^2[/tex]
(where (h, k) is the center of the circle and r is the radius)
Given equation:
[tex]\sf (x-3)^2+y^2=4[/tex]
Rewrite in standard form:
[tex]\sf \implies (x-3)^2+(y-0)^2=2^2[/tex]
Therefore
- center = (3, 0)
- radius = 2
