Answer:
- Parent Function: [tex]y=\sqrt{x}[/tex]
- Horizontal shift: right 3 units
- Vertical shift: up 3 units
- Reflection about the x-axis: none
- Vertical strech: streched
Step-by-step explanation:
assume that [tex]y=\sqrt{x}[/tex] is [tex]f(x)=\sqrt{x}[/tex] and [tex]y=\sqrt{-2x+6}+3[/tex] is
[tex]g(x)=\sqrt{-2x+6}+3\\ f(x)=\sqrt{x} \\g(x)=\sqrt{-2x+6}+3[/tex]
The transformation from the first equation to the second equation can be found by finding a,h and k for each equation.
[tex]y=a\sqrt{x-h}+k[/tex]
factor a 1 out of the absolute value to make the coefficient of x equal to 1
[tex]y=\sqrt{x}[/tex]
factor a 2 out of the absolute value to make the coefficient of x equal to 1
[tex]y=\sqrt{2}\sqrt{x-3}+3[/tex]
find a, h and k for [tex]y=\sqrt{2}\sqrt{x-3}+3[/tex]
[tex]a=1.41421356\\ h=3\\k=3[/tex]
the horizontal shift depends on the value of h when [tex]h > 0[/tex], the horizontal shift is described as:
[tex]g(x)=f(x+h)[/tex] - the graph is shifted to the left h units
[tex]g(x)=f(x-h)\\[/tex] - the graph is shifted to the right h units
the vertical shift depends on the value of k
